Difference between revisions of "MongoDB QueryData"

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  db.dept.find({_id:10})
 
  db.dept.find({_id:10})
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In the ''emp'' collection, the _ids are system generated and generally along the lines of: 5a0727e99ba81dee9b1cc6a3 so less easy to use!
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List all the records in emp:
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db.emp.find().pretty()
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and pick one an _id from the collection and then try and find one record. For example (note, your object id will be different):
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 +
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db.emp.find( {_id : ObjectId("5a0727e99ba81dee9b1cc6a3")}).pretty()
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The function ''ObjectId'' must be used to convert the value into an object id.
  
 
== Next Step ==
 
== Next Step ==
  
 
[[MongoDB_Aggregate_Pipeline|MongoDB Aggregation]] Pipeline
 
[[MongoDB_Aggregate_Pipeline|MongoDB Aggregation]] Pipeline

Revision as of 17:10, 11 November 2017

Main Page >> MongoDB >>MongoDB Workbook >> Querying Collections

Querying a collection

The find() function can be used to query the documents.

The format is:

 db.collectionName.find(optional_query_criteria)

Where the query_criteria follows a pattern:

 db.collectionName.find({keyField: "value"})

Note:

  • the criteria is enclosed in curly brackets: {}
  • the value needs quotes if it is a string or date value
  • all names and values are case sensitive
  • quotes are optional for the fieldName, so long as they do not contain spaces


Find all documents

For example, show all the data so far in the dept collection:

db.dept.find()

And the emp collection:

db.emp.find()


The data comes back messy. The pretty() function can be used to improve the layout:

db.emp.find().pretty()


Note the difference in the object ids returned.


Find with query criteria

If working with a large collection, you will not want all the documents returned.

Find all the employees in department 10:

db.emp.find({deptno:10})


Find One document

To find just one document requires the use of the equivalent of a primary key field. This can be a field that the user takes responsibility to keep unique, such as the deptno:

db.dept.find({deptno:10})


Or the object id can be used, which will be unique:

db.dept.find({_id:10})


In the emp collection, the _ids are system generated and generally along the lines of: 5a0727e99ba81dee9b1cc6a3 so less easy to use!

List all the records in emp:

db.emp.find().pretty()

and pick one an _id from the collection and then try and find one record. For example (note, your object id will be different):


db.emp.find( {_id : ObjectId("5a0727e99ba81dee9b1cc6a3")}).pretty()


The function ObjectId must be used to convert the value into an object id.

Next Step

MongoDB Aggregation Pipeline